Find the young Modulus of a brass rod of diameter 25 mm and of length 250mm which is subjected to a tensile load of 50kN when the extension of the rod is equal to 0.3 mm.?
Detailed Solution:
stress = force/area = 50000N/0.785 x 25 x 25 = 101.91 N/sq(mm) strain = extension of rod/original length of rod = 0.3/250 = 0.0012 now, modulus of elasticity = stress/strain = 101.91/0.0012 = 84925 N/sq(mm)