A can do a piece of work in 7 days of 9 hours each, and B can do it in 6 days of 7 hours each. How long will they take to do it, working together 8 2/5 hours a day?
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Work done by A in 10 days=10/80=1/8 Remaining work=(1-(1/8))=7/8 Now, work will be done by B in 42 days. Whole work will be done by B in (42*8/7)=48 days Therefore, A's one day's work=1/80 B’s one day's work=1/48 (A+B)'s one day's work=1/80+1/48=8/240=1/30 Hence, both will finish the work in 30 days.
A can complete the work in (7*9) = 63 days B can complete the work in (6*7) = 42 days --> A’s one hour’s work = 1/63 and B’s one hour work = 1/42. (A+B)’s one hour work = 1/63+1/42 = 5/126 Therefore, Both can finish the work in 126/5 hours. Number of days of 8 2/5 hours each = (126*5/(5*42)) = 3 days
Whole work will be done by X in 10*4 = 40 days. Whole work will be done by Y in (40*100/40) = 100 days. Whole work will be done by Z in (13*3) = 39 days Therefore, Z will complete the work first.
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