A rod 150 cm long and of diameter 2.0 cm is subjected to an axial pull of 20kN. If the modulus of elasticity of the material of the rod is 2 x 10^5 N/Sq(mm) ; determine : the stress?
Detailed Solution:
Area of Rod:- (Ï€/4)(radius^2) :- 100Ï€ sq(mm), now, Stress= Force/Area = 20000/100Ï€ = 63.662 N/sq(mm)