A rod of 150cm long and of diameter 2.0 cm is subjected to an axial pullof 20kN. If the modulus of elasticity of the material of the rod is 2 x 10^5 N/sq(mm), determine strain?

Detailed Solution:

we know that, Modulus of elasticity is stress/strain, stress is equal to force/area, hence by putting value of Area = 0.785 x diameter x diameter, and force is equal to 20000 N, we get stress equal to 63.662 N/sq(mm), now, from the equation of hookes law, strain = stress/modulus of elasticity = 63.662/200000 = 0.000318